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2.68xx10^(-3) moles of solution containi...

`2.68xx10^(-3)` moles of solution containing anion `A^(n+)` require `1.61xx10^(-3)` moles of `MnO_(4)^(-)` for oxidation of `A^(n+)` to `AO_(3)^(-)` in acidic medium. What is the value of `n`?

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" Eq of "`A^(+n)=" Eq of "MnO_(4)^(ɵ)`
`2.68xx10^(-3)(5-n)=1.61xx10^(-3)xx5` (n factor)
`napprox2`
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