`n`-butane is produced by the monobromination of ethane followed by Wurtz reaction. Calculate the volume of ethane at `NTP` to produce `55 g` n-butane if the bromination takes place with `90%` yield and the Wurtz reaction with `85%` yield.

Explanation

`2CH_(3)-CH_(3)+Br_(2)overset(Light)to2CH_(3)-CH_(2)Br+2HBr`
`2CH_(3)-CH_(2)Broverset((Na)/(ether))toCH_(3)-CH_(2)-CH_(2)-CH_(3)`
Moles of butane `=(55)/(58)`
Moles of `CH_(3)-CH_(2)Br` required `=2xx(55)/(58)xx(100)/(85)`
(Because reaction yield is `85%`)
Moles of `CH_(3)-CH_(3)` reqruied`=2xx(55)/(58)xx(100)/(85)xx(100)/(90)`
(Because reaction yield is `90%`)
Volume of `CH_(3)-CH_(3)` required at STP is
`2xx(55)/(58)xx(100)/(85)xx(100)/(90)xx22.4=55.533L`