Around `20%` surface sites have adsorbed `N_(2)`. On heating `N_(2)` gas evolved form sites and were collected at 0.001 atm and 298 K in a container of volume `2.46cm^(3)` the density of surface sites is `6.023xx10^(14)cm^(-2)` and surface area is `1000cm^(2)` find out the number of surface sites occupied per molecule of `N_(2)`.

Explanation

Density of sites `=6.023xx10^(14)`
Total sites `=6.023xx10^(14)xx1000`
`=6.023xx10^(17)`
`20%` sites are occupied.
So sites occupied`=(20)/(100)xx6.023xx10^(17)`
`=12.04xx10^(16)`
`PV=nRT`
or `n+(0.001xx2.46xx10^(-3))/(0.821xx300)=9.98xx10^(-9)`
Molecules`=9.98xx10^(-9)xx6.023xx10^(23)`
`=6.02xx10^(16)`
Sites occupied per molecule of nitrogen is
`("Number of sites")/("Number of molecules")=(12.04xx10^(16))/(6.02xx10^(16))=2`