A hydrogen like atom in ground st6ate abserbs n photon having the same energy and its emit exacity n photon when electron transition tekes placed .Then the energy of the absorbed photon may be

Options

A. `91.8 eV`
B. `40.8 eV`
C. `48.4 eV`
D. `54.4 eV`

Answer

A, B

Explanation

Exp: Number of dark line (inabsorption ), i.e. excittation = Number of bright lines its emission i.e. de -excitation
It is possible only when the e is excitated `n = 2` from ground state
Clearly `Delta E = 91.8 eV ` and `40.8 eV` are possible
`Li^(2+) (He^(o+))`