`5 L` of nitrogen measured at `750 mm` have to be compressed into an iron cylinder of `1 L` capacity. If temperature is kept constant, calculate the pressure in atmospheres required to do so.

Explanation

Given
`V_(1)= 5L`
`P_(1)=750 mm` or `(750)/(760)atm`
`V_(2)=1 L`
`P_(2)=?`
` :. P_(1)V_(1)=P_(2)V_(2)`
or `P_(2)=(P_(1)V_(1))/(V_(2))=((750)/(760)xx5)/(1)`
`:. P_(2)=4.93 atm`