`152 mL` of a gas at `STP` was taken to `20^(@)C` and `729 mm` pressure. What was the change in volume of the gas?

Explanation

Given
`V_(1)=152 mL`
`P_(1)=1 atm=760 mm`
`T_(1)=273.15 K`
`V_(2)=?`
`P_(2)=729 m`
`T_(2)=20^(@)C` or `293.15 K`
`:. V_(2)=(P_(1)V_(1))/(T_(1))xx(T_(2))/(P_(2))=(760xx152xx293.15)/(273.15xx729)=170 mL`
`:. Change in volume=V_(2)-V_(1)=170-152=18 mL`