Hydrogen gas obtained by electrolysis of `18g` of water is heated to `127^(@)C` at a pressure of `2 atm`. Calculate the volume it would occupy.

Explanation

`H_(2)O overset(Electrolysis)(rarr) H_(2)+(1)/(2)O_(2)`
`1 mol` of `H_(2)O=18 g`
`implies 1 mol` of `H_(2)` at `STP=22.4 L` at `STP`
Volume of `H_(2)` at `127^(@)C(127+273=400 K)` and `2 atm` pressure is
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`
`{:(P_(1)= 1 atm, P_(2)=2 atm),(T_(1)=273 K, T_(2)=400K),(V_(1)=22.4 L, V_(2)=?):}`
`V_(2)=(P_(1)V_(1)T_(2))/(P_(2)T_(1))=(1xx22.4xx400)/(2xx273)=16.4L`