A certain quantity of gas occupies `50 mL` when collected over water at `15^(@)C` and `750 mm` pressure. It occupies `45.95 mL` in the dry state at `NTP`. Find the partial pressure of water vapour at `15^(@)C`.

Explanation

`{:(V_(1)= 50 mL, V_(2)=45.95 mL),(P_(1)=750-x, P_(2)=1 atm=760mm),(T_(1)=273+15=288K, T_(2)=273K):}`
`((750-x)xx50)/(288)=(760xx45.95)/(273)`
`:. X=13.3 mm`