`127 mL` of a certain gas diffuses in the same time as `100 mL` of chlorine under the same conditions. Calculate the molecular weight of the gas.

Explanation

`(V_(1))/(V_(2))=sqrt((d_(2))/(d_(1)))=sqrt((M_(2))/(M_(1)))`
`(127)/(100)=sqrt((71)/(M_(1)))`
`:. M_(1)=43.58`