A sample of gas is taken in a closed vessel at `20^(@)C`. The gas is heated until the pressure is doubled. What is the final temperature?

Explanation

Given
`T_(1)=20^(@)C=293.15K`
`P_(1)=P`
`T_(2)=?`
`P_(2)=2P`
using `P_(1)//T_(1)=P_(2)//T_(2)impliesT_(2)=P_(2)T_(1)//P_(1)`
or `T_(2)=313.15^(@)C`