A diver uses noen- oxygen mixture containing 7.4 g oxygen and 167.5 g neon for respiretion under water. If the pressure partial pressures of oxygen and neon in the mixture? Atomic mass of oxygen is u and that of neon is 20.2 u.

Explanation

`n_(O_(2))=(70.4)/(32)=2.2` mol
`n_(Ne)=(167.5)/(20.2)=8.29mol`
total moles `=2.2+8.29=10.49`
mole fractions
`O_(2)=(2.2)/(10.49)=0.2097approx0.21,Ne=0.79`
pressure due to total moles (10.49)=25bar
`p_(O_(2))=0.21xx25=5.25` bar
`p_(Ne)=0.79xx25=19.75` bar.