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A 4 : 1 molar mixture of He and CH(4) is...

A `4 : 1` molar mixture of `He` and `CH_(4)` is contained in a vessel at `20` bar pressure. Due to a hole in the vessel, the gas mixture leaks out. What is the composition of the mixture effusing out initially?

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Applying graham's law of effusion,
`(r_(He))/(r_(CH_(4)))=sqrt((M_(CH_(4)))/(M_(He)))=sqrt(16)/(4)=sqrt(4)=2`
therefore, he diffuses two times faster than `CH_(4)`
`therefore` molar ratio of the He: `CH_(4)` effusing out initially `=8:1`
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