20 `dm^(3)` of `SO_(2)` diffuse through a porous partition in 60 s. what volume of `O_(2)` will diffuse under similar conditions in 30 s ?

Explanation

`r_(SO_(2))=(20dm^(3))/(60s)=(1)/(3)dm^(3)s^(-1)`
`r_(O_(2))=(vdm^(3))/(30s)=(v)/(30)dm^(3)s^(-1)`
Applying graham's law of diffusion
`(r_(O_(2)))/(r_(SO_(2)))=sqrt((M_(SO_(2)))/(M_(O_(2))))`
or `(v//30)/(1//3)=sqrt((64)/(32))`
or `(v)/(10)=sqrt(2)impliesv=14.14dm^(3)`