Calculate the enthalpy of combustion of benzene `(l)` on the basis of the following data:
a. Resonance energy of benzene `(l) =- 152 kJ// mol`
b. Enthalpy of hydrogenation of cyclohexene `(l) =- 119 kJ//mol`
c. `Delta_(f)H^(Theta)C_(6)H_(12)(l) =- 156 kJ mol^(-1)`
d. `Delta_(f)H^(Theta) of H_(2)O(l) =- 285.8 kJ mol^(-1)`
e. `Delta_(f)H^(Theta)of CO_(2)(g) =- 393.5 kJ mol^(-1)`

Explanation

`-357 = Delta_(f)H^(Theta)C_(6)H_(12) (l) - Delta_(F)H^(Theta)("benzene")`
`Delta_(f)H^(Theta)("benzene") =-156 +357 = 210 kJ mol^(-1)`
Resonance enrgy `=Delta_(f)H^(Theta)underset(Actual)("benzene")-Delta_(f)H^(Theta)underset("Theoretical")("benzene")`
`underset(Actual)(Delta_(f)H^(Theta))("benzene") =- 156 +201 = 49 kJ mol^(-1)`

`DeltaH^(Theta) = 6Delta_(f)H^(Theta)CO_(2)(g) +3Delta_(f)H^(Theta)H_(2)O(l)-Delta_(f)H^(Theta)("benzene")`
`= 6 (-393.5) +2(-285.8) - 49 =- 3267.4 kJ mol^(-1)`