Home
Class 11
CHEMISTRY
Delta(vap)S of acetone is 90.0 J K^(-1) ...

`Delta_(vap)S` of acetone is `90.0 J K^(-1) mol^(-1)`. If boiling point of acetone is `50^(@)C`, calculate the heat required for the vaporisation of `1g` of acetone..

Text Solution

Verified by Experts

`Delta_(vap)H = Delta_(vap)S xx T_(b) = 90.0 xx323 = 29070.0J mol^(-1)`
Heat required to vaporise `1g` acetone
` = (29070)/(50) = 581.4J`
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    CENGAGE CHEMISTRY|Exercise Ex 6.5|30 Videos
  • THERMODYNAMICS

    CENGAGE CHEMISTRY|Exercise Exercises (Subjective)|70 Videos
  • THERMODYNAMICS

    CENGAGE CHEMISTRY|Exercise Ex 6.3|27 Videos
  • STOICHIOMETRY

    CENGAGE CHEMISTRY|Exercise Archives Subjective|33 Videos

Similar Questions

Explore conceptually related problems

Delta_(vap) S1 of acetone is 93.0 JK^(-1) "mol"^(-1) .If boiling point of acetone is 56^(@)C , calculate the heat required for the vaporisation of 1 g of acetone.

Molar entropy change is 16 J mol^(-1)K^(-1) , the boiling points of the liquid is if molar heat of vaporization is 6 kJ/mol.

0.70 g of an organic compund when dissolved in 32g of acetone produces in an elevation in boiling point of 0.25^(@)C . Calculate the molecular mass of the organic compound. (K_(b)" for acetone "=1.72 K kg mol^(-1)) .

A solution containing 7g of a solute (molar mass 210 "g mol"^(-1) ) in 350g of acetone raised the boiling point of acetone from 56^(@)C to 56.3^(@)C . The value of ebullioscope contant of acetone in "K kg bol"^(-1) is :

Calculate the enthalpy of vaporisation per mole for ethanol. Given DeltaS = 109.8 J K^(-1) mol^(-1) and boiling point of ethanol is 78.5^(@) .

The entropy change for vaporisation of a liquid is 109.3JK^(-1)mol^(-1) . The molar heat of vaporisation of that liquid is 40.77 kJ mol^(-1) . Calculate the boiling point of that liquid.