The enthalpy of vaporisation of benzene `(C_(6)H_(6))` is `30.8 kJ mol^(-1)` at its boiling point `(80.1^(@)C)`. Calculate the entropy change in going from:
a. liquid to vapour and
b. vapour to liquid at `80.1^(@)C`.

Explanation

To calculate the entropy change for the given processes involving benzene, we can follow these steps:

### Given Data:
- Enthalpy of vaporization of benzene, \( \Delta H_{vap} = 30.8 \, \text{kJ/mol} \)
- Boiling point of benzene, \( T = 80.1^\circ C \)

### Step 1: Convert the boiling point to Kelvin
To convert Celsius to Kelvin, we use the formula:
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