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Calculate the entropy change at 298K for...

Calculate the entropy change at `298K` for the reaction
`Br_(2)(l) +CI_(2)(g) rarr 2BrCI(g)`
`DeltaH = 29.3 kJ at 298K`. The entropies of `Br_(2)(l), CI_(2)(g)`, and `BrCI(g)` at the above temperature and `152.3, 223.0` and `239.7 J mol^(-1)K^(-1)` respectively.

Text Solution

Verified by Experts

For the reaction,
`DeltaH = 29.3 kJ = 29300J`
`DeltaS = S ("products") -S ("reactants")`
`= 2xxS (BrCI) -[S(Br_(2))+S(CI_(2))]`
`= 2 xx 239.7 - [152.3 +223.0]`
`= 479.4 - 375.3`
`= 104.1J`
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