An athelete is given `100g` of glucose `(C_(6)H_(12)O_(6))` of energy equivalent to `1560 kJ`. He utilises `50%` of this gained enegry in the event. In order to avoid storage of enegry in the body, calculate the weight of water he would need to perspire. The enthalpy of evaporation of water is `441kJ//mol`.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the energy utilized by the athlete.
The total energy from 100g of glucose is given as 1560 kJ. The athlete utilizes 50% of this energy.

\[ \text{Energy utilized} = \frac{50}{100} \times 1560 \, \text{kJ} = 780 \, \text{kJ} \]
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