How much hea is liberated when one mole of gaseous `Na^(o+)` combines with one mole of `CI^(Theta)` ion to form solid `NaCI`. Use the data given below:
`{:(Na(s)+(1)/(2)CI_(2)(g)rarrNaCI(s),,DeltaH =- 98.23 kcal),(Na(s)rarrNa(g),,DeltaH =+25.98 kcal),(Na(g)rarrNa^(o+)+e^(-),,DeltaH =+120.0 kcal),(CI_(2)(g)rarr2CI(g),,DeltaH =+58.02 kcal),(CI^(Theta)(g)rarrCI(g)+e^(-),,DeltaH=+87.3kcal):}`

Explanation

`{:(Na^(o+)(g)+CI^(Theta)(g)rarrNaCI(s),,DeltaH_(U)=?),(Given:,,),(Na(s)+(1)/(2)CI_(2)(g)rarrNaCI(s),,DeltaH_(1)=-98.23kcal),(Na(s)rarrNa(g),,DeltaH_(2)=25.98kcal),(Na(g)rarrNa^(o+)(g)+e^(-),,DeltaH_(3)=120.0kcal),((1)/(2)CI_(2)(g)rarr2CI(g),,DeltaH_(4)=58.02xx(1)/(2)kcal),(CI^(Theta)(g)rarrCI(g)+e^(-),,DeltaH_(5)=873kcal):}`
`{:("Rewritting equations:",,),(Na(s)+(1)/(2)CI_(2)(g)rarrNaCI(s),,DeltaH_(1)=-98.23),(Na(g)rarrNa(s),,DeltaH_(2)=25.98),(Na^(o+)(g)+e^(-)rarrNa(g),,DeltaH_(3)=-120.0),((1)/(2)[CI_(2)(g)rarr(1)/(2)CI(g)],,DeltaH_(4)=-58.02xx(1)/(2)),(CI(g)rarrCI(g)+e^(-),,DeltaH_(5)=87.3),(ulbar(Na^(o+)(g)+CI^(Theta)rarrNaCI(s)),,):}`
`DeltaH = 98.23 -25.98 - 120.0 - 58.02 xx (1)/(2) +87.3`
`=- 185.92 kcal`
or `DeltaH = DeltaH_(1) - DeltaH_(2) -DeltaH_(3) - (1)/(2)DeltaH_(4) -DeltaH_(5)`
`=- 98.23 - 25.98 - 12.0 -(1)/(2) xx 58.02 +87.3`
`= - 185.92 kcal`