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Calculate the entropy change for the fol...

Calculate the entropy change for the following reaction
`H_(2)(g) +CI_(2)(g) rarr 2HCI (g) at 298 K`
Given `S^(Theta)H_(2) = 131 J K^(-1) mol^(-1), S^(Theta)CI_(2) = 233 J K^(-1) mol^(-1)`, and `S^(Theta) HCI = 187 J K^(-1) mol^(-1)`

Text Solution

Verified by Experts

`DeltaS^(Theta) = sum S^(Theta)(Products) - sum S^(Theta) (Reactant)`
`= 2xx187 -(131 +223)`
`= 374 - 131 - 223 = 20 J K^(-1) mol^(-1)`
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