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Find DeltaH of the following reaction: ...

Find `DeltaH` of the following reaction:
`OF_(2)(g) +H_(2)O(g) rarr O_(2)(g)+2HF (g)`, average bond energies of `O -F, O-H, O =O`, and `H - F` are `44,111, 118`, and `135 kcal mol^(-1)`, respectively.

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`OF_(2)(g) +H_(2)O(g) rarr O_(2)(g) +2HF(g), DeltaH = ?`
`BE` of reactant `=2(O-F) +2(O-H)`
`= 2 xx 44 +2 xx 11 = 310 kcal`
`BE` of products
`O = O +2 (H-F)`
`= 118 +2 xx 135 = 388 kcal, DeltaH = H_(P) - H_(R)`
`DeltaH = 310 - 388 =- 78 kcal`
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