Calculate heat of dissociation for acetic acid from the following data:
`CH_(3)COOH +NaOH rarr CH_(3)COONa +H_(2)O DeltaH = - 13.2 kcal`
`H^(o+) +overset(Theta)Ohrarr H_(2)O, DeltaH =- 13.7 kcal`
Also calculate heat of dissociation for `NH_(4)OH` if
`HCI +NH_(4)OH rarr NH_(4)CI +H_(2)O, DeltaH =- 12.27 kcal`

Explanation

`CH_(3)COOH(w_(A)) +overset(Theta)OH (s_(B)) rarr CH_(3)COO^(Theta) = H_(2)O, DeltaH_(1) =- 13.2 kcal`
`H^(o+)(S_(A)) +overset(Theta)OH(S_(B)) rarr H_(2)O DeltaH_(2) = 13.7 kcal`
`DeltaH = DeltaH_(1) - DeltaH_(2)`
`=- 13.2 - (-23.7) = 0.5 kcal`
Similarly, for `NH_(4)OH:`
`Na_(4)OH rarr NH_(4)^(o+) +overset(Theta)OH, DeltaH = ?`
`H^(o+)(S_(A)) +NH_(4) OH (W_(B)) rarr NH_(4)^(o+) +H_(2)O, DeltaH_(1) = 12.27`
`H^(o+)+overset(Theta)OH rarr H_(2)O`
`{:ulbar(NH_(4)OH rarr NH_(4)^(o+)+overset(Theta)OH):}`
`DeltaH = DeltaH_(1) - DeltaH_(2) = - 12.7 -(-13.7) = 1.43 cal`