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DeltaG=DeltaH-TDeltaS and ltBRgt DeltaG...

`DeltaG=DeltaH-TDeltaS` and ltBRgt `DeltaG=DeltaH+T[(d(DeltaG))/(dT)]_(p),` then` ((dE_(cell))/(dT))` is

A

`(DeltaH)/(nF)`

B

`(DeltaG)/(nF)`

C

`(DeltaS)/(nF)`

D

`-(DeltaS)/(nF)`

Text Solution

Verified by Experts

On comparison:
`DeltaS =- [(d(DeltaG))/(dT)]`
`DeltaS =- (d(-nFE))/(dT) = nF ((dF)/(dT)) [{:("Here E is the"),(E_(mf) "of cell"):}]`
`:. ((dE)/(dT)) = (DeltaS)/(nF)`
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