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The heat of neutralisation of oxalic aci...

The heat of neutralisation of oxalic acid is `-25.4 kcal mol^(-1)` using strong base, `NaOH`. Hence, the enthaly change of the process is
`H_(2)C_(2)O_(4) hArr 2H^(o+) +C_(2)O_(4)^(2-)` is

A

`2.0 kcal`

B

`-11.8 kcal`

C

`1.0 kcal`

D

`-1.0 kcal`

Text Solution

Verified by Experts

Oxalic acid has two ionisable `H^(o+)`. Hence, expected heat of neutralisation, if it behaves as a strong acid would have been
`=- 13.7 xx2=- 27.4 kcal mol^(-1)`
But experimetal value `=- 25.4 kcal mol^(-1)`
`:.` Heat of ionisation `= 2.0 kcal mol^(-1)`
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Statement-I : The enthalpy of neutralization of the reaction between HCl and NaOH is -13.7 kCal/mol. If the enthalpy of neutralization of oxalic acid (H_(2)C_(2)O_(4)) by a strong base is -25.4 kCal/mol, then the enthalpy change (|Delta_(r)H|) of the process H_(2)C_(2)O_(4) rarr 2H^(+)+C_(2)O_(4)^(2-) is 11.7 kCal/mol. Statement-II : H_(2)C_(2)O_(4) is a weak acid.

Heat of neutralization between HCl and NaOH is -13.7 kcal "equiv"^(–1) . Heat of neutralization of H_2C_2O_4 (oxalic acid) with NaOH is -26 kcal mol^(-1) . Hence, heat of dissociation of H_(2)C_(2)O_(4) as H_2C_2O_(4) rarr 2H^(+) + C_(2)O_(4)^(2-) , is :

Heat of neutralisation of oxalic acid is -53.35 kJ/g.eq. using NaOH. Calculate the value of Detla H for the given reaction H_(2)C_(2)O_(4) hArr C_(2)O_(4)^(2-) + 2H^(+)

The enthalpy of neutralization of oxitic acid by strong acid is 25.4 kcal mol^(-1) . The enthalpy of neutralization of strong acid and strong base is -13.7 kcal equil^(-1) . The enthalpy of dissociation of H_(2)C_(2)O_(4)hArr2H^(+)+C_(@)O_(4)^(2-) is

Heat of neutralisation of oxalic acid is -106.7 KJ mol^(-1) using NaOH hence Delta H of : H_(2)C_(2)O_(4)rarr C_(2)O_(4)^(2-)+2H^(+) is :-

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