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Calculate heat of formation of KOH(s) us...

Calculate heat of formation of `KOH(s)` using the following equations
`K(s) +H_(2)O(l) +aq rarr KOH(aq)+1//2 H_(2)(g),DeltaH =- 48.0 kcal …(i)`
`H_(2)(g) +1//2O_(2)(g) rarr H_(2)O(l),DeltaH =- 68.4 kcal …(ii)`
`KOH(s) +(aq) rarr KOH(aq),DeltaH =- 14.0 kcal ....(iii)`

A

`-68 +48 - 14`

B

`-68 - 48 +14`

C

`68 - 48 +14`

D

`68 +48 +14`

Text Solution

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Calculate heat of formation of KOH(s) using the following equations K(s) +H_(2)O(l) +aq rarr KOH(aq)+1//2 H_(2)O(g),DeltaH =- 48.0 kcal …(i) H_(2)(g) +2O_(2)(g) rarr H_(2)O(l),DeltaH =- 68.4 kcal …(ii) KOH(s) +(aq) rarr KOH(aq),DeltaH =- 14.0 kcal ....(iii)

Calculate the enthalpy of formation of KOH(s) from the following data : K(s) + H_(2)O(l) + (aq) to KOH(aq) + 1/2 H_(2)(g) Delta_(r)H^(@) = -200.8 kJ H_(2)(g) + 1/2 O_(2)(g) to H_(2)O(l) Delta_(r)H^(@) = - 286.3 kJ KOH(s) + (aq) to KOH(aq) Delta_(r)H^(@) = - 58.6 kJ

Calculate the heat of combustion of benzene form the following data: a. 6C(s) +3H_(2)(g) rarr C_(6)H_(6)(l), DeltaH = 49.0 kJ b. H_(2)(g) +1//2O_(2)(g) rarr H_(2)O(l), DeltaH =- 285.8 kJ c. C(s) +O_(2) (g) rarr CO_(2)(g), DeltaH =- 389.3 kJ

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