`Delta_("sub")H=`………………..`+`………………. .

Use the following data to calculate Delta_("lattice")H^(@) for NaBr. Delta_("sub")H^(@) for sodium metal = 108.4 kJ "mol"^(-1) .Ionization enthalpy of sodium = 496 kJ "mol"^(-1) Electron gain enthalpy of bromine = -325 kJ "mol"^(-1) .Bond dissociation enthalpy of bromine = 192 kJ "mol"^(-1) . Delta_(f)^(H^(@)) for NaBr (s) = -360.1 kJ "mol"^(-1) .

Use the following data to calculate Delta_("lattice") H^(@) for NaBr. Delta_("sub")H^(@) for sodium metal =108.4 kJ mol^(-1) , ionization enthalpy of sodium =496 kJ mol^(-1) ., electron gain enthalpy of bromine =-325 kJ mol^(-1) bond dissociation enthalpy of bromine =192 kJ mol^(-1) , Delta _f H^(@) for NaBr(s) - 360 kJ mol^(-1) .

Calculate the enthalpy change of 1 mole of reaction Na(s)+(1)/(2)Br_(2)(g)rarrNaBr(s) in kcal Given : Delta H_("sub")(Na)=137 kJ "mole"^(-1) , DeltaH_("bond dissociation")(Br_(2)(g))=144 kJ "mole"^(-1) Delta H_("1 st ionisation")(Na(g)=496 kJ "mole"^(-1) , Delta H_(1 st "electron affinity")(Br(g)=-325 kJ "mole"^(-1) Delta H_("Lattice energy")(NaBr)= +742

For an ideal solution, Delta_(mix)V is ……….and Delta_(mix)H is ………. .

The expression Delta_("sub"1)H^(Theta) =Delta_(fus)H^(Theta) +Delta_(vap)H^(Theta) is true at al