In the moles of ethane `(C_(2)H_(6))`, calculate the following:
a. Number of moles of carbon atoms
b. Number of moles of hydrogen stoms
c. Number of molecules of ethane.

Explanation

a. `1 mol` of `C_(2)H_(6)` contains `2 mol` of `C` atoms.
`:. 3` mol of `C_(2)H_(6)` will contains `C` atoms `=6 mol`
b. `1 mol` of `C_(2)H_(6)` contains `6 mol` of `H` atoms.
`:. 3` mol of `C_(2)H_(6)` will contain `H` atoms `=18 mol`
c. `1 mol` of `C_(2)H_(6)` contains Avogadro's number., i.e., `6.02xx10^(23)` molecules.
`:. 3` mol of `C_(2)H_(6)` will contain ethane molacules
`=3xx6.02xx10^(23)=18.06xx10^(23)` molecules