The following data are obtained when dinitrogen and dioxygen react to gether to form different compounds:
`{:(,,"Mass of dinitrogen",,"Mass of dioxygen"),(i.,,14 g,,16 g),(ii.,,14 g,,32 g),(iii.,,28 g,,32 g),(iv.,,28 g,,80 g):}`
a. Which law of chemical combination is obeyed by the above experimental data? Give its statement.
b. Fill in the blanks in the following conversions:
I. `1 km=` ....... `mm=` ......pm
II. `1 mg=` ........ `kg=` ......... ng
III. `1 mL=` ........` L=`......... `dm^(3)`

Explanation

Fixing the mass of dinitrogen as `28 g`, masses of dioxygen combined will be `32, 64, 32`, and `80 g` in the given four oxides. These are in the ratio `1:2:1:5` which is a simple whole number ratio. Hence, the given data obey the law of multiple proportions.
b. i. `1 km=1 kmxx(1000 m)/(1 km)xx(100 cm)/(1 m)xx(10 mm)/(1 cm)=10^(6) mm`
`1 km=1 kmxx(1000 m)/(1 km)xx(1 "pm")/(10^(-12)m)=10^(15) "pm"`
ii. `1 mg=1 mgxx(1g)/(1000mg)xx(1 kg)/(1000 g)=10^(-6) kg`
`1 mg=1 mgxx(1g)/(1000 mg)xx(1 ng)/(10^(-9)g)=10^(6) ng`
iii. `1 mL=1 mLxx(1L)/(1000mL)=10^(-3) L`
`1 mL=1 cm^(3)`
`=1 cm^(3)xx(1dmxx1dmxx1dm)/(10 cmxx10 cmxx10 cm)=10^(-3) dm^(3)`