Chlorine is prepared in the laboratory by treating manganese dioxide `(MnO_(2))` with aqueous hydrochloric acid according to the reaction,
`4HCl_((aq))+MnO_(2(s))rarr2H_(2)O_(l)+MnCl_(2(aq))+Cl_(2(g))`
How many gram of `HCl` react with `5.0 g` of manganese water to make `250.0mL` solution.

Explanation

`Mw` of `MnO_(2)=55+32=87 g`
`1` mol `(i.e., 87 g)` of `MnO_(2)` reacts with `4 mol` of `HCl`
`(i.e., 4xx36.5 g)=146 g` of `HCl`
`5.0 g` of `MnO_(2)` will react with `HCl=146/87xx5.0=8.40 g`