Balance the following rebox reactions by ion electron method:
a. `MnO_(4)^(Θ)(aq)+I^(Θ)(aq) rarr MnO_(2)(s)+I_(2)(s)` (in basic medium)
b. `MnO_(4)^(Θ)(aq)+SO_(2)(g) rarr Mn^(2+)(aq)+HSO_(4)^(Θ)(aq)` (in acidic solution)
c. `H_(2)O_(2)(aq)+Fe^(2+)(aq) rarr Fe^(3+)(aq)+H_(2)O(l)` (in acidic solution)
d. `Cr_(2)O_(7)^(2-)+SO_(2)(g) rarr Cr^(3+)(aq)+SO_(4)^(2-)(aq)` (in acidic solution)

Explanation

To balance the given redox reactions using the ion-electron method, we will follow a systematic approach for each reaction. Here’s how to do it step by step:

### a. Balancing `MnO4^-(aq) + I^-(aq) → MnO2(s) + I2(s)` in Basic Medium

1. **Identify Oxidation and Reduction:**
- **Oxidation:** I⁻ → I₂ (oxidation state changes from -1 to 0).
- **Reduction:** MnO₄⁻ → MnO₂ (oxidation state changes from +7 to +4).

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