In Ostwald's process for the manufacture of nitric acid, the first step involves the oxidation of amonia gas by oxygen gas to give nitric oxide gas and steam. What is the maximum weight of nitric oxide that can obtained starting only with `10.00 g` of ammonia and `20.00 g` of oxygen?

Explanation

To solve the problem of determining the maximum weight of nitric oxide (NO) that can be obtained from the given amounts of ammonia (NH₃) and oxygen (O₂) in Ostwald's process, we will follow these steps:

### Step 1: Write the balanced chemical equation
The balanced equation for the reaction of ammonia with oxygen to produce nitric oxide and water is:
\[ 4 \text{NH}_3(g) + 5 \text{O}_2(g) \rightarrow 4 \text{NO}(g) + 6 \text{H}_2O(g) \]

### Step 2: Calculate the molar masses
- Molar mass of NH₃ (Ammonia) = 14 (N) + 3 × 1 (H) = 17 g/mol
...