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In a process, 701 J of heat is obsorbed ...

In a process, `701 J` of heat is obsorbed by a system and `394 J` of work is done by the system. What is the change in internal energy for the process?

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`q=+701 J, w=-394 J, DeltaU=?`
By first law of thermodynamics
`DeltaU=q+w`
`=+701 J+(-394 J)=+307 J`
i.e., internal of the system increases by `307 J`.
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