The reaction of cyanamide, `NH_(2)CN(s)`, with dioxygen was carried out in a bomb calorimeter, and `DeltaU` was found to be `-742.7 kJ mol^(-1)` at `298 K`. Calculate enthalpy change for the reaction at `298 K`.
`NH_(2)CN(g)+3/2O_(2)(g) rarr N_(2)(g)+CO_(2)(g)+H_(2)O(l)`

Explanation

To calculate the enthalpy change (\( \Delta H \)) for the reaction of cyanamide with dioxygen, we can use the relationship between internal energy change (\( \Delta U \)) and enthalpy change (\( \Delta H \)) given by the formula:

\[ \Delta H = \Delta U + \Delta N_g RT \]

Where:
- \( \Delta N_g \) = Change in the number of moles of gas
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