Calculate the standard enthalpy of formation of `CH_(3)OH(l)` from the following data:
`CH_(3)OH(l)+3/2O_(2)(g) rarr CO_(2)(g)+2H_(2)O(l), …(i), Delta_(r)H_(1)^(Θ)=-726 kJ mol^(-1)`
`C(g)+O_(2)(g) rarr CO_(2)(g), …(ii), Delta_(c )H_(2)^(Θ)=-393 kJ mol^(-1)`
`H_(2)(g)+1/2O_(2)(g) rarr H_(2)O(l), ...(iii), Delta_(f)H_(3)^(Θ)=-286 kJ mol^(-1)`

Explanation

To calculate the standard enthalpy of formation of \( CH_3OH(l) \) from the given data, we will use Hess's law. We need to arrange the provided reactions to derive the formation reaction of \( CH_3OH \).

### Step-by-Step Solution:

1. **Write the formation reaction of \( CH_3OH \)**:
The standard enthalpy of formation is defined for the reaction:
\[
C(s) + 2H_2(g) + \frac{1}{2}O_2(g) \rightarrow CH_3OH(l)
...