Calculate the enthalpy change for the process
`C Cl_(4)(g) rarr C(g)+4Cl(g)`
and calculate bond enthalpy of `C-Cl` in `C Cl_(4)(g)`.
`Delta_(vap)H^(Θ)(C Cl_(4))=30.5 kJ mol^(-1)`
`Delta_(f)H^(Θ)(C Cl_(4))=-135.5 kJ mol^(-1)`
`Delta_(a)H^(Θ)(C )=715.0 kJ mol^(-1)`, where `Delta_(a)H^(Θ)` is enthalpy of atomisation
`Delta_(a)H^(Θ)(Cl_(2))=242 kJ mol^(-1)`

Explanation

To calculate the enthalpy change for the process:

\[ \text{CCl}_4(g) \rightarrow \text{C}(g) + 4\text{Cl}(g) \]

and to find the bond enthalpy of the C-Cl bond in CCl₄, we can follow these steps:

### Step 1: Write down the given data

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