`20.0 g` of ammonium nitrate `(NH_(4)NO_(3))` is dissolved In `125 g` of water in a coffee-cup calorimeter, the temperature falls from `296.5 K` to `286.4 K`. Find the value of `q` for the calorimeter. (Hint: heat capacity of water as the heat capacity of the calorimeter and its content)

Explanation

To solve the problem of finding the heat transfer \( q \) for the calorimeter when 20.0 g of ammonium nitrate is dissolved in 125 g of water, we can follow these steps:

### Step 1: Identify the given values
- Mass of water \( m = 125 \, \text{g} \)
- Initial temperature \( T_1 = 296.5 \, \text{K} \)
- Final temperature \( T_2 = 286.4 \, \text{K} \)
- Specific heat capacity of water \( C = 4.18 \, \text{J/g} \cdot \text{K} \)

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