Home
Class 12
CHEMISTRY
In sapphire, oxide ions are arranged in ...

In sapphire, oxide ions are arranged in hexagonal close packing and aluminium ions occupy two-thirds of the octahedral voids. What is the formula of sapphire?

Text Solution

Verified by Experts

The correct Answer is:
`Al_(2)O_(3)`
Let number of anion `O^(2-) = 1//"atom"`
Number of `TV = 2// "atom"`
Number of `OV = 1//"atom"`
Number of cation `(Al^(3+)) = (2)/(3) xx 1 = (2)/(3)`
Formula: `Al^(3+)_(2//3)O^(2-)` or `Al_(2)O_(3)`.
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    CENGAGE CHEMISTRY|Exercise Ex 1.1 (Objective)|19 Videos

  • SOLID STATE

    CENGAGE CHEMISTRY|Exercise Ex 1.2 (Subjective)|2 Videos

  • SOLID STATE

    CENGAGE CHEMISTRY|Exercise Exercises (Archives ) Subjective|9 Videos

  • REDUCTION AND OXIDATION REACTION OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY|Exercise SUBJECTIVE TYPE|3 Videos

  • SOLUTIONS

    CENGAGE CHEMISTRY|Exercise Ex 2.3 (Objective)|9 Videos

Similar Questions

Explore conceptually related problems

In corundum, oxide ions are arranged in hexagonal close packing and aluminium ionsa occpy tow-third of the octaheral voids. What is the formula of corrundum ? .

(i) In corundum, oxide ions are arranged in hexagonal close packing and aluminium ions occupy two third of octahedral voids. What is the formula of corundum ? (ii) The unit cell of silver iodide (Agl) has 4 iodine atoms in it. How many silver atoms must be there in the unit cell ?

In a metal oxide , the oxide ions are arranged in hexagonal close packing and metal lone occupy two - third of the ocishedral voids .The formula of the oxide is

In corrundum, oxid ions are arranged in h.c.p. array and the aluminum ions occupy two - thirds of octahedral voids. What is the formula of currundum ?

The anions A from hexagonal close packing and atoms (M) occupy only two-third of the octahedral voids. The general formula of the compound is

In a compound,oxide ions are arranged in cubic close packing arrangement. Cations A occupy one-sixth of the tetrahdral voids and cations B occupy one-third of the octahedral voids. The formula of the compound is