The `EMF` of Westron standard cell is `1.0153` at `20^(@)C` and `1.01807` at `25^(@)C`. Calculate`DeltaG,DeltaH,` and `Delta S` for the cell reaction at `25^(@)C`.

Explanation

For Westron cadmium cell,`n_(cell)=2`.
`((delE)/(delT))_(p)=((1.01807-1.01530))/((298-293))=5.54xx10^(-4)Vdeg^(-1)`
`DeltaS=nF((delE)/(delT))_(p)`
`=2xx96500Cxx5.54xx10^(-4)Vdeg^(-1)`
`=106.9Jdeg^(-1)=106.9xx10^(-3)kJdeg^(-1)`
`Delta G=-nFE=-2 xx 96500xx1.01807(` at `25^(@)C)`
`=-196.45kJmol^(-1)`
`DeltaH=-DeltaG+T DeltaS`
`=-196.45kJ+298xx106.9xx10^(-3)kJ mol^(-1)`
`=-196.45+31.85=-164.6k J mol^(-1)`
`Delta H=nF[T((delE)/(delT))_(p)-E]`
`=2xx96500[298xx5.54xx10^(-4)-1.01807]`
`=-164.58kJ mol ^(-1)~~164.kJ mol^(-1)`