The `EMF` of the cell `:`
`Cd|CdCl_(2)(` solution `)(1atm)|AgCl(s)|Ag` is `0.675` at `25^(@)C`. The temperature coefficient of the cell is `-6.5xx10^(-4)` `d e g r e e^(-1)`. Find the change in heat content and entropy for the electrochemical reaction that occurs when `1F` of electricity is drawn for it.

Explanation

`E_(cell)=0.675V`
Cell reaction is `:`
Anode reaction
`(1)/(2) Cd(s) rarrr(1)/(2) Cd^(2+)(aq)+e^(-)`
Cathode reaction `:`
`AgCl(s)+e^(-) rarr Ag(s)+Cl^(c-)(aq)`
Cell reaction `:`
`ulbar((1)/(2)Cd(s)+AgClhArrAg(s)+(1)/(2)Cd^(2+)(aq)+Cl^(c-)(aq))`
Temperature coefficient of the cell , `i.e.,`
`((delE)/(delT))_(P)=-6.5xx10^(-4)Vdeg^(-1)`
`DeltaS+nF((delE)/(delT))_(P)" "(n_(cell=1)`
`=1xx96500 xx(-6.5xx10^(-4))`
`=-65.73V deg^(-1)`
`E=-(DeltaH)/(nF)+T((delE)/(delT))_(P)`
`0.675V=(-DeltaH)/(1xx96500)+298(-6.5xx10^(-4))`
`DeltaH=-83829.55J~~-83.83kJ mol ^(-1)`