Find `K_(c)` for the complex`:`
`[Ag(NH_(3))_(2)]^(o+)hArrAg^(o+)+2NH_(3)`
`E^(c-)._((Ag^(o+)//Ag))=0.8V` and `E^(c-)._{[Ag(NH_(3))_(2)]^(o+)|Ag|NH_(3))=0.37V`

Explanation

Anode reaction `:` `cancel(Ag) hArrAg^(o+)+cancel(e^(_))`
Cathode reacion `:[Ag(NH_(3))_(2)]^(o+)hArrcancel(Ag)+2NH_(3)`
Cell reaction`ulbar( :[Ag(NH_(3))_(2)]^(o+)hArrAg^(o+)+2NH_(3))`
`E^(c-)._(cell)=(E^(c-)._(reduction))_(c)=(E^(c-)._(reduction))_(a)`
`=0.37V-0.8V=-0.43V`
`:. log K_(c)=(n_(cell)xxE^(c-)._(cell))/(0.0059)`
`=(1xx(-.43V))/(0.59)=-7.22`
`K_(c)=Anti l og(-7.22)`
`=Antil og(-7-022+1-1)`
`=Antil og(bar(8).78)=6xx10^(-8)`