If the `EMF` of the above cell is `0.03V,E_(SC E)=0.24V,E^(c-)._(glass)=0.51V,` then calculate the `pH` of buffer solution at `30^(@)C`.

Explanation

`E_(glass)=E^(c-)._(glass)-0.06pH(` at `30^(@)C)`
`E_(SCE)=0.24V`
`:. E_(cell)=E_(RHS)-E_(LHS)`
`=E_(SCE)-E_(glass)`
`0.03V=0.24V-(E^(c-).glass)-0.06pH)(` at `30^(@)C)`
`implies0.03V=0.24V-(0.51-0.06pH)`
`:. pH=(E_(cell)-0.24+E^(c-)._(glass))/(0.06)`
`=(0.03-0.24+0.51)/(0.06)=5`