`1F` of electricity is passed through `10 L` of a solution of aqueous solution of `NaCl` . Calculate the `pH` of the solution.

Explanation

Aqueous `NaCl` solution on electrolysis gives `Cl_(2)(g)` at anode and `H_(2)(g)` at cathode and `overset(c-)(O)H` ions in the solution.
`1F=1` equilvalent of `H_(2)(g)=1` equivalent of `Cl_(2)(g)` and `=1`Equivalent of `overset(c-)(O)H` ions
`:. [overset(c-)(O)H]=("Equivalent")/("Volume of solution in L")=(1)/(10L)=10^(-1)N` or `M`
`:. pOH=-log (10^(-1))=1`
`pH=14-1=13`