What weight of `Ni` is plated out in an electrolysis of aqueous `NiSO_(4)` solution that it takes place to deposit `2G` OF `Ag` in a silver coulometer that is arranged in series with `NiSO_(4)` electrolytic cell. `[` Atomic weight of `Ag=107.8 am u , ` atomic weight of `Ni=58.7 am u]`

Explanation

Applying Faraday's second law of electrolysis,
`(W of Ni)/(W of Ag)=(Ew of Ni)/(Ew of Ag)`
`W_(Ni)=(W_(Ag)xx Ew(Ni))/(Ew(Ag)) [{:(Ew of Ag,=(At omic weight )/(n fact o r) ),(,=(107.8)/(1)):}]`
`=(2g xx 58.7//2)/(107.8//1)[{:(Ew of Ni,=(At omic weight )/(n fact o r) ),(,=(58.7)/(2)):}]`
`=0.5445g g of Ni` deposited