`100mL `of `1M` solution of `CuBr_(2)` was electrolyzed with a current of `0.965` ampere hour. What is the normality of the remaining `CuBr_(2)` solution ?
`a. 1.64" "b.3.28" "c.0.82" "d.4.92`

Explanation

`a.` Initial `mEq` of `Cu^(2+)=V(mL)xxN`
`=100xx1xx2`
`('n'` factor for `Cu^(2+)=2)`
`=200mEq`
Electricity passed `=(0.965xx3600)/(96500)`
`=36xx10^(-3)Eq`
`=36mEq`
`mEq` of `CuBr` remaining `=200-36=164`
`:. N=(mEq)/(V(i n mL))=(164)/(100)=1.64`