Find the volume of gases evolved by passing `0.1 A` of current for `965s`, through an aqueous solution of sodium succinate at `27^(@)C` and `1 atm`.

Explanation

Reduction at anode of `H_(2)O` takes place.
`2H_(2)O+2e^(-) rarr 2 overset(c-)(O)H+H_(2)uarr`
`[` Since reduction potential of `H_(2)Ogt` reduction potential of `Na^(o+)]`
`[1mol `o f `C_(2)H_(4)+1mol ` of `H_(2)+2 mol `of `CO_(2)]`
`2F` or `2xx96500C` of electricity produces
`=4xx22.4L ` of gases at both electrodes at `STP.`
`:. 0.1 xx965C` will give `=(4xx22.4)/(2xx96500)xx0.1xx965`
`=44.8 mL`
Volume at `27^(@)C(300K)` and 1 atmosphere pressure
`(V_(1))/(T_(1))=(V_(2))/(T_(2))implies(44.8)/(273)=(V_(2))/(300)`
`:. V_(2)=(44.8xx300)/(273)=49.23mL`