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wedge(m)^(@) for NaCl,HCl, and NaAc are1...

`wedge_(m)^(@)` for `NaCl,HCl`, and `NaAc` are`126.4, 425.9,` and `91.0 S cm^(2) mol^(-1)` , respectively . Calculate `wedge ^(@)` for `Hac.`

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`wedge_(m(HAc))^(@)=wedge_(m(HCl))^(@)wedge_(m(NaAc))^(@)+wedge_(m(NaCl))^(@)`
`=(425.9+91.0-126.4)S cm^(2)mol^(-1)`
`=390.5 S cm^(2) mol^(-1)`
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