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Cu^(2+)+2e^(-) rarr Cu. On increasing [C...

`Cu^(2+)+2e^(-) rarr Cu.` On increasing `[Cu^(2+)]`, electrode potential

A

Increases

B

Decreases

C

No change

D

First increases, then decreases

Text Solution

Verified by Experts

The correct Answer is:
a
`Cu^(2+)(aq)+2e^(-)rarrCu(s)` ltbr. `E_(Cu^(2+)|Cu)=E^(c-)._(Cu^(2+)|Cu)-(0.059)/(2)log .(1)/([Cu^(2+)])`
`=E^(c-)._(Cu^(2+)|Cu)+(0.059)/(2)log.[Cu^(2+)]`
If `[Cu^(2+)]` increases, `E_(Cu^(2+)|Cu)` also increases.
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