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Consider the following E^@ values . E(F...

Consider the following ` E^@` values . `E_(Fe^(3+)//Fe^(2+)^@ = + 0.77 V`,
`E_(Sn^(2+)//Sn)^@=- 15. V` The `E_(cell)^@` for the reaction ,
`Sn (s) + 2Fe_(aq)^(3+) rarr 2 Fe_(aq.)^(2+) + Sn_(aq.)^(2+) is :

A

`-0.58 V`

B

`-0.30 V`

C

`+0.30V`

D

`+0.58 V`

Text Solution

Verified by Experts

The correct Answer is:
c
At anode `: Fe(s) rarr Fe^(2+)(aq)+2e^(-)`
`(` hald oxidation `)`
At cathode `: Sn^(2+)(aq)+2e^(-) rarr Sn(s)`
`(` half reduction `)`
`ulbar(Cell reaction : Fe(s)+Sn^(2+)(aq)rarr Fe^(2+)(aq)+Sn(s))`
`E^(c-)._(cell)=(E^(c-)._(red))_(c)-(E^(c-)._(red))_(a)`
`=(-0.14)-(0.44)=0.30V.`
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CENGAGE CHEMISTRY-ELECTROCHEMISTRY-Ex 3.1 (Objective)
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