For the reaction `:`
`A+2B^(3+) rarr 2B^(2+)+A^(2+)`
`E^(0)` of the given redox reaction is `:`
`A^(2+)+2e^(-) rarr A` `E^(0)=xV`
`B^(3+)+e^(-) rarr B^(2+)` `E^(0)=yV`

Options

A. `x-2y`
B. `x+y//2`
C. `x-y`
D. `y-x`

Answer

D

Explanation

It is a redox reaction, thus
Cell reaction `:`
At anode `: A rarr A^(2+)+2e^(-)(` Oxidation `)`
`E^(c-)._(o x i d)=-xV,E^(c-)._(red)=xV`
At cathode `: 2B^(3+)2e^(-) rarr 2B^(2+)(` Reduction `)`
`E^(c-)._(red)=yV`
`ulbar(Cell reaction : A+2B^(3+) rarr A^(2+)+2B^(2+))`
`E^(c-)._(cell)=(E^(c-)._(red))_(c)-(E^(c-)._(red))_(a)=(y-x)V`