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The number of moles of Zn^(2+) ions depo...

The number of moles of `Zn^(2+)` ions deposited when a current of `1.5A` is passed for 4 hours through a molten solution of a zince salt. `(` Assume current efficiency to be `90%)`

A

`6.35`

B

`0.1`

C

`0.4`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
b
`(Zn^(+2)+2e^(-)rarr Zn)`
`Q=Axxtxx(90)/(100)`
`=(1.5xx4xx60xx60xx90)/(100)`
`=19440C`.
`2F=96500Cxx2C=1mol of Zn`
`19440 C =(19440)/(96500xx2)=(19440)/(193000)~~0.1 mol`
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